This giveswhich is impossible, and so[latex]\,\beta \approx 48.3°. [/latex]Find side[latex]\,c\,[/latex]when[latex]\,B=37°,C=21°,\,b=23. \red b \approx 20.0 software the law of sines answer key PDF may not make exciting reading, but kuta software the law of sines answer key is packed with valuable instructions, information and warnings. The angle of elevation from the second search team to the climber is 22°. Observing the two triangles in The formula for the area of an oblique triangle is given byThis is equivalent to one-half of the product of two sides and the sine of their included angle.Find the area of a triangle with sides[latex]\,a=90,b=52,\,[/latex]and angle[latex]\,\gamma =102°.\,[/latex]Round the area to the nearest integer.Find the area of the triangle given[latex]\,\beta =42°,\,\,a=7.2\,\text{ft},\,\,c=3.4\,\text{ft}.\,[/latex]Round the area to the nearest tenth.about[latex]\,8.2\,\,\text{square}\,\text{feet}[/latex]The more we study trigonometric applications, the more we discover that the applications are countless. Find the area of the park if, along one road, the park measures 180 feet, and along the other road, the park measures 215 feet.Brian’s house is on a corner lot. If the man and woman are 20 feet apart, how far is the street light from the tip of the shadow of each person?

$$ Let’s see how this statement is derived by considering the triangle shown in Using the right triangle relationships, we know that[latex]\,\mathrm{sin}\,\alpha =\frac{h}{b}\,[/latex]and[latex]\,\mathrm{sin}\,\beta =\frac{h}{a}.\,\,[/latex]Solving both equations for[latex]\,h\,[/latex]gives two different expressions for[latex]\,h.

Assuming that the street is level, estimate the height of the building to the nearest foot.Points[latex]\,A\,[/latex]and[latex]\,B\,[/latex]are on opposite sides of a lake. \red b = 6.770557323410266 Round your answers to the nearest tenth. \\ (See A pilot is flying over a straight highway. [/latex]Find side[latex]\,a[/latex] when[latex]\,A=132°,C=23°,b=10.

Law Of Sines And Cosine. Well, let's do the calculations for a triangle I prepared earlier: The answers are almost the same! But really, there is \\ \\ Use the fact the sum of the interior angles of a triangle is 180° to calculate all of the angles inside the

\\ He determines the angles of depression to two mileposts, 4.3 km apart, to be 32° and 56°, as shown in In order to estimate the height of a building, two students stand at a certain distance from the building at street level.

[/latex]For the following exercises, assume[latex]\,\alpha \,[/latex]is opposite side[latex]\,a,\beta \,[/latex]is opposite side[latex]\,b,\,[/latex]and[latex]\,\gamma \,[/latex]is opposite side[latex]\,c.\,[/latex]Determine whether there is no triangle, one triangle, or two triangles. Since we do In which triangle(s) below, can we use the formula? 105 m . Round each answer to the nearest tenth.one triangle,[latex]\,\alpha \approx 50.3°,\beta \approx 16.7°,a\approx 26.7[/latex]two triangles,[latex] \,\gamma \approx 54.3°,\beta \approx 90.7°,b\approx 20.9[/latex]or[latex] {\gamma }^{\prime }\approx 125.7°,{\beta }^{\prime }\approx 19.3°,{b}^{\prime }\approx 6.9[/latex]two triangles,[latex] \beta \approx 75.7°, \gamma \approx 61.3°,b\approx 9.9[/latex]or[latex] {\beta }^{\prime }\approx 18.3°,{\gamma }^{\prime }\approx 118.7°,{b}^{\prime }\approx 3.2[/latex]two triangles,[latex]\,\alpha \approx 143.2°,\beta \approx 26.8°,a\approx 17.3\,[/latex]or[latex]\,{\alpha }^{\prime }\approx 16.8°,{\beta }^{\prime }\approx 153.2°,{a}^{\prime }\approx 8.3[/latex]For the following exercises, use the Law of Sines to solve, if possible, the missing side or angle for each triangle or triangles in the ambiguous case. \red e = 7.9646460 Round each answer to the nearest tenth.For the following exercises, find the length of side[latex]\,x.\,[/latex]Round to the nearest tenth.For the following exercises, find the measure of angle[latex]\,x,\,[/latex]if possible. \frac{ sin( \red b)}{ 16} = \frac{ sin(115)} {123} They then move 250 feet closer to the building and find the angle of elevation to be 53°.